CS146 FINALS OT

1.

1 point

The data of the velocity of a body as a function of time is given as follows.

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 12

30.429

27.867

43.000

28.333

2.

1 point

Truncation error is caused by

rational numbers

exact mathematical procedures

irrational numbers

fractions

3.

1 point

(1101)base2=(?)base10

10

3

8

13

4.

1 point

If for a real continuous function f(x), you have f(a)f(b)<0, then in the interval [a,b] for f(x)=0, there is (are)

one root

an undeterminable number of roots

no root

at least one root

5.

1 point

The goal of forward elimination steps in the Naïve Gauss elimination method is to reduce the coefficient matrix to a (an) _____________ matrix.

lower triangular

identity

diagonal

upper triangular

6.

1 point

(25.375)base10 = (?)base2

10011.0011

11001.011

10011.110

100110.011

7.

1 point

(25)base10=(?)base2

10011

11001

110010

100110

8.

1 point

The following data of the velocity of a body as a function of time is given as follows.
Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123

43.000

30.429

28.333

27.867

9.

1 point

The following data is given for the velocity of the rocket as a function of time. To find the velocity at t=21 s, you are asked to use a quadratic polynomial, v(t)=at^2+bt+c to approximate the velocity profile.

[227.04,362.78,517.35]

[0,362.78,517.35]

[517.35,602.97,901.67]

[362.78,517.35,602.97]

10.

1 point

The next iterative value of the root of using secant method, if the initial guesses are 3 and 4, is 4

2.2857

5.5000

2.5000

5.7143

11.

1 point

Assuming an initial bracket of [1,5] , the second (at the end of 2 iterations) iterative value of the root of te^-1 - 0.3 = 0 is

0.0

2.0

1.5

2.5

12.

1 point

Representing 2 in a fixed point register with 2 bits for the integer part and 3 bits for the fractional part gives a round off error of most nearly

0.1642

-0.085709

0.0392

0.2892

13.

1 point

The bisection method of finding roots of nonlinear equations falls under the category of a (an) ______ method.

open

random

graphical

bracketing

14.

1 point

Using a computer with four significant digits with chopping, the Naïve Gauss elimination solution to

0.0030X1 +55.23X2 = 58.12
6.239X1 - 7.123X2 = 47.23

x1 = 8.769;X2 = 1.051

x1 = 26.66;X2 = 1.051

x1 = 8.771;X2 = 1.052

x1 = 8.800;X2 = 1.000

15.

1 point

The Lagrange polynomial that passes through the 3 data points is given by
x 15 18 22
y 24 37 25

–0.071430

4.3333

0.50000

0.57143

16.

1 point

The following gas stations were cited for irregular dispensation by the Department of Agriculture. Which one cheated you the most?

She

Ser

Cit

Hus