CS146 FINALS OT

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1.
1 point
The following gas stations were cited for irregular dispensation by the Department of Agriculture. Which one cheated you the most?
2.
1 point
The Lagrange polynomial that passes through the 3 data points is given by
x 15 18 22
y 24 37 25
3.
1 point
Using a computer with four significant digits with chopping, the Naïve Gauss elimination solution to

0.0030X1 +55.23X2 = 58.12
6.239X1 - 7.123X2 = 47.23
4.
1 point
The bisection method of finding roots of nonlinear equations falls under the category of a (an) ______  method.
5.
1 point
Representing 2 in a fixed point register with 2 bits for the integer part and 3 bits for the fractional part gives a round off error of most nearly
6.
1 point
Assuming an initial bracket of [1,5] , the second (at the end of 2 iterations) iterative value of the root of te^-1 - 0.3 = 0 is
7.
1 point
The next iterative value of the root of using secant method, if the initial guesses are 3 and 4, is 4
8.
1 point
The following data is given for the velocity of the rocket as a function of time.  To find the velocity at t=21 s, you are asked to use a quadratic polynomial, v(t)=at^2+bt+c to approximate the velocity profile.
9.
1 point
The following data of the velocity of a body as a function of time is given as follows.
Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 123
10.
1 point
(25)base10=(?)base2
11.
1 point
(25.375)base10 = (?)base2
12.
1 point
The goal of forward elimination steps in the Naïve Gauss elimination method is to reduce the coefficient matrix to a (an) _____________ matrix.
13.
1 point
If for a real continuous function f(x), you have f(a)f(b)<0, then in the interval [a,b] for f(x)=0, there is (are)
14.
1 point
(1101)base2=(?)base10
15.
1 point
Truncation error is caused by
16.
1 point
The data of the velocity of a body as a function of time is given as follows.

Time (s) 0 15 18 22 24
Velocity (m/s) 22 24 37 25 12